1.

The number of electrons that have a total charge of 9650 coulombs is …………………. .

Answer»

`6.22 xx 10^(23)`
`6.022 xx 10^(24)`
`6.022 xx 10^(22)`
`6.022 xx 10^(-34)`

SOLUTION :IF = `96500C = 1 "mole of " e^(-) = 6.023 xx 10^(23) e^(-)`
`:. 9650 C = (6.22 xx 10^(23))/(96500) = 6.022 xx 10^(22)`.


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