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The number of elements that a square matrix of order n has below its leading diagonal, isA. `(n(n+1))/2`B. `(n(n-1))/2`C. `((n-1)(n-1))/2`D. `((n+1)(n+1))/2`

Answer» Correct Answer - B
There `aren^2` elements in a square matrix of order n out of which n elements other than diagonal elemenets is `(n^2-n)`.
Half of these elements are above the diagonal and half are below the diagonal.
So, required number of elements is `(n^2-n)/2=1/2n(n-1)`.


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