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The number of integral values of n such that the equation 2n{x} = 3x + 2[x]has exactly 5 solutions. |
Answer» x=I+F 2nf=3(I+F)+2I `f=(5I)/(2n-3)` `0<=(5I)/(2n-3)<1` `0<=I/(2n-3)<1/5` `f=(5I)/(2n-3)=(5I)/(17)` `f=(5I)/14` `f=(5I)/21` `f=(5I)/23` `f=(5I)/25` `f=(5I)/27` option b is correct. |
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