1.

The number of integral values of n such that the equation 2n{x} = 3x + 2[x]has exactly 5 solutions.

Answer» x=I+F
2nf=3(I+F)+2I
`f=(5I)/(2n-3)`
`0<=(5I)/(2n-3)<1`
`0<=I/(2n-3)<1/5`
`f=(5I)/(2n-3)=(5I)/(17)`
`f=(5I)/14`
`f=(5I)/21`
`f=(5I)/23`
`f=(5I)/25`
`f=(5I)/27`
option b is correct.


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