1.

The number of isomeric pentyl alcohols possible is

Answer»

Two
Four
Six
Eight

Solution :Draw all possible isomers having all single bonds in them and count their total number.
(i) `CH_(3)CH_(2)CH_(2)CH_(2)CH_(2)OH`
(ii) `{:(CH_(3)CH_(2)CH_(2)CH_(2)CH_(3)),("|"),(""OH):}`
(iii) `{:(CH_(3)CH_(2)CH-CH_(2)CH_(3)),("|"),(""OH):}`
(IV) `{:(CH_(3)CH_(2)CH-CH_(2)OH),("|"),(""CH_(3)):}`(V) `{:(""OH),("|"),(CH_(3)CH_(2)C-CH_(3)),("|"),(""CH_(3)):}`
(vi) `{:(""CH_(2)OH),("|"),(CH_(3)CH_(2)CH-CH_(3)):}`(vii) `{:(""CH_(3) ),("|"),(CH_(3)-C-CH_(2)OH),("|"),(""CH_(3)):}`
(viii) `{:(""CH_(2)-OH),("|"),(CH_(3)-C-CH_(3)),("|"),(""CH_(3)):}`


Discussion

No Comment Found

Related InterviewSolutions