1.

The number of isomers of C_(6)H_(14) is

Answer»

4
5
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7

Solution :(i) `CH_(3)-CH_(2)-CH_(2)-CH_(2)-CH_(2)-CH_(3)`
(ii) `{:(CH_(3)-CH-CH_(2)-CH_(2)-CH_(3)),("|"),(""CH_(3)):}`
(iii)`{:(CH_(3)-CH-CH-CH_(3)),("|""|"),(""CH_(3)" "CH_(3)):}`
(iv) `{:(""CH_(3)),("|"),(CH_(3)-C-CH_(2)-CH_(3)),("|"),(""CH_(3)):}`
(V) `{:(CH_(3)-CH_(2)-CH-CH_(2)-CH_(3)),("|"),(""CH_(3)):}`


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