InterviewSolution
Saved Bookmarks
| 1. |
The number of molecules in 22.4 cm3 of nitrogengas at STP is |
|
Answer» In 1 mole of gas , the no. of L = 22.4 L = 22.4*1000 cm³. = 22400cm³. now for 22.4cm³ , the no. of moles will be = 22.4/22400 = 0.001 so the no. of moleculws will be 0.001*(6×10^23) = 6×10^20 molecules. |
|