1.

The number of molecules in 22.4 cm3 of nitrogengas at STP is

Answer»

In 1 mole of gas , the no. of L = 22.4 L = 22.4*1000 cm³. = 22400cm³. now for 22.4cm³ , the no. of moles will be = 22.4/22400 = 0.001 so the no. of moleculws will be 0.001*(6×10^23) = 6×10^20 molecules.



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