The number of moles in 3.00 g of boron tribromide BBr3 is 'x' ×10−2 – InterviewSolution

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1.	The number of moles in 3.00 g of boron tribromide BBr3 is 'x' ×10−2. 'x' is .
Answer» The number of moles in 3.00 g of boron tribromide $B B r_{3}$ is 'x' $\times 10^{- 2}$ . 'x' is .

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