The number of neutrons emitted when ""_(92)^(235) U undergoes controll – InterviewSolution

1.	The number of neutrons emitted when ""_(92)^(235) U undergoes controlled nuclear fission to ""_(54)^(142) Xe and ""_(38)^(90) Sr is
Answer» Solution :`""_(92) U^(235) + ""_(0) n^(1) to ""_(54) Xe^(142) + ""_(38) Sr^(90) + y(""_(1) n^(0)) , (235 + 1) = (142 + 90) + y` `y = (236- 232) = 4` NET no. of .n. emitted = `(4 - 1)` = 3

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