1.

The number of neutrons emitteed when ._(92)^(235)U undergoes controlled nulclear fission to ._(54)^(142)Xe and ._(38)^(90)Sr is:

Answer»


Solution :`._(92)^(235)U+._(0)n^(1) rarr ._(54)^(142) Xe+._(38)^(142)Xe+._(38)^(90)Sr+x ._(0)n^(1)`
Applying MASS number balance
`235+1=142+90+x`
`x=4`


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