1.

The number of photons emitted per second by a 60 watt source of monochromaticlight of wavelength 663 nm is (h=6.63xx10^(-34)Js)

Answer»

`4xx10^(-20)`
`1.5xx10^(20)`
`3XX10^(-20)`
`2XX10^(20)`

Solution :Energy of one photon `E=hv=(HC)/(lamda)`
`=(6.63xx10^(-34)xx3.0xx10^(8))/(663xx10^(-9))`
NO. of PHOTONS `=60/((6.63xx10^(-34)xx3.0xx10^(8))/(663xx10^(-9)))`
`=(60xx663xx10^(-9))/(6.63xx10^(-34)xx3.0xx10^(8))=2xx10^(20)`


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