The number of photons falling per second on a completely darkened plate to produce force of 6.62xx10^(-5) N is n . If the wavelength of the light falling is 5xx10^(-7) m then n = ............ xx 10^(22). ( h = 6.62 xx10^(-34)J s )

The number of photons falling per second on a completely darkened plat

1.	The number of photons falling per second on a completely darkened plate to produce force of 6.62xx10^(-5) N is n . If the wavelength of the light falling is 5xx10^(-7) m then n = ............ xx 10^(22). ( h = 6.62 xx10^(-34)J s )
Answer» 1 5 0.2 3.3 Solution :`P=n/t(hc)/lamda` `FC=n/t(hC)/lamda` `n/t=(Flamda)/h` `n/t=(6.62xx10^(-5)xx5xx10^(-7))/(6.62xx10^(-34))` = `5xx10^(22)`

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The number of photons falling per second on a completely darkened plate to produce force of 6.62xx10^(-5) N is n . If the wavelength of the light falling is 5xx10^(-7) m then n = ............ xx 10^(22). ( h = 6.62 xx10^(-34)J s )

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