1.

The number of photons of wavelength 13.2A^(@)in 6J of energy is (h=6.6xx10^(-34)J.s)

Answer»

`2xx10^(12)`
`4xx10^(16)`
`6xx10^(20)`
`4xx10^(24)`

SOLUTION :As `n=(E lambda)/(hc)`
`:.n=(6xx13.2xx10^(-10))/(6.6xx10^(-34)xx3xx10^(8))`
or `n=4xx10^(16)`


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