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The number of photons of wavelength `540 nm` emitted per second by an electric bulb of power `100 W` is (taking `h = 6 xx 10^(-34) sec`)A. `100`B. `1000`C. `3 xx 10^(20)`D. `3 xx 10^(18)` |
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Answer» Correct Answer - C `P = (nhc)/(lambda t) rArr 100 = (n xx 6 xx 10^(-34) xx 3 xx 10^(8))/(540 xx 10^(-9) xx 1)` `rArr n = 3 xx 10^(20)` |
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