Saved Bookmarks
| 1. |
The number of possible enantiomeric pairs that can be produced during mono-chlorination of 2-methylbutane is |
|
Answer» 3 Its monochloro derivatives are as follows : (i) `{:(ClCH_(2)-overset(*)(C)H-CH_(2)-CH_(3)),("|"),(""CH_(3)):}` or `{:(CH_(3)-overset(*)(C)H-CH_(2)-CH_(3)),("|"),(""CH_(2)Cl):}` It will exist as enantiomeric pair (d and l-forms) (ii) `{:(""Cl),("|"),(CH_(3)-C-CH_(2)-CH_(3)),("|"),(""CH_(3)):}` no asymmetric C-atom (iii) `{:(""Cl),("|"),(CH_(3)-CH-CH-CH_(3)),("|"),(""CH_(3)):}` It will exist as enantiomeric pair (d-and l-forms) (iv) `{:(CH_(3)-CH-CH_(2)-CH_(2)-Cl),("|"),(""CH_(3)):}` No asymmetric carbon atom Hence, only TWO enantiometric pairs will be obtained by the monochlorination of 2-methylbutane. |
|