1.

The number of possible open chain (acyclic) isomeric compounds for molecular formula C_(5)H_(10) would be

Answer»

`8`
`7`
`6`
`5`

SOLUTION :`C_(5)H_(10)` has `1^(@)` DEGREE of UNSATURATION since the isomers are ACYCLIC, all of these are alkanes. For writing the isomers, FIRST introduce the double bond at different possible positions, and then consider the possibility of branching in the alkyl group.
`underset("1-pentene (i)")(CH_(3)CH_(2)CH_(2)CH=CH_(2))""underset("2-pentene, (cis,-trans) (ii),(iii)")(CH_(3)CH_(2)CH=CHCH_(3))`
`underset("3-methyl-1-butene, (iv)")(CH_(3)-overset(CH_(3))overset(|)(C)H-CH=CH_(2))""underset("2-methyl-1-butene, (v)")(CH_(3)CH_(2)overset(CH_(3))overset(|)(C)=CH_(2))`
`underset("2-methyl-2-butene, (vI)")(CH_(3)-overset(CH_(3))overset(|)(C)=CHCH_(3))`.


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