The number of real roots of quadratic equation (x-4)2 +(x-5)2+(x-6)2=0 – InterviewSolution

1.

The number of real roots of quadratic equation (x-4)2 +(x-5)2+(x-6)2=0 is

Answer»

Answer:14/11

Step-by-step explanation:

2X + 8 + 7X - 10 + 2x- 10= 0

11x - 14 = 0

11x = 14

X = 14/11

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