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The number of revolutions per second made by an electron in the first Bohr orbit of hydrogen atom is of the order of `3`:A. `6.57xx10^(15)`B. `6.57xx10^(13)`C. `1000`D. `6.57xx10^(14)` |
Answer» Correct Answer - A `v_(1)(t)=n.2pir_(1)Rightarrown=?` |
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