The number of silicon atoms per m^(3) is 5 xx 10^(28). This is doped simultaneously with 5 xx 10^(22) atoms per m^(3) of Arsenic and 5 xx 10^(20) per m^(3) atoms of Indium. Calcualte the number of electrons and holes. Given that n_(i) = 1.5 xx 10^(16) m^(-3). Is the material n-type or p-type?

The number of silicon atoms per m^(3) is 5 xx 10^(28). This is doped s

1.	The number of silicon atoms per m^(3) is 5 xx 10^(28). This is doped simultaneously with 5 xx 10^(22) atoms per m^(3) of Arsenic and 5 xx 10^(20) per m^(3) atoms of Indium. Calcualte the number of electrons and holes. Given that n_(i) = 1.5 xx 10^(16) m^(-3). Is the material n-type or p-type?
Answer» SOLUTION :`n_(C) = 4.95 xx 10^(22), n_(h) = 4.75 xx 10^(9)`, n-type since `n_(e) gt gt n_(h)` For CHARGE neutrality `N_(D)-N_(A) = n_(e).n_(h) = n_(i)^(2)` Solving these equations, `n_(e) = 1/2 [(N_(D)-N_(A)) + sqrt((N_(D)-N_(A))^(2) + 4n_(i)^(2))]`

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The number of silicon atoms per m^(3) is 5 xx 10^(28). This is doped simultaneously with 5 xx 10^(22) atoms per m^(3) of Arsenic and 5 xx 10^(20) per m^(3) atoms of Indium. Calcualte the number of electrons and holes. Given that n_(i) = 1.5 xx 10^(16) m^(-3). Is the material n-type or p-type?

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