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The number of silicon atoms per m^(3) is 5xx10^(28). This is doped simultaneously with 5xx10^(22) atoms per m^(3) of Arsenic and 5xx10^(20) per m^(3) atoms of Indium. Calculate the number of electrons and holes. Given that n_(i)=1.5xx10^(16)m^(-3). Is the material n-type or p-type? |
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Answer» SOLUTION :Here number of atoms of Arsenic per `m^(3)` is, `N_(D)=5xx10^(22)` and number of atoms of Indium per `m^(3)` is, `N_(A)=5xx10^(20)` `therefore` Number of electrons per `m^(3)`, `n_(e )=N_(D)-N_(A)=(5xx10^(22)-0.05xx10^(22))` `=4.95xx10^(22)` but `n_(i)^(2)=n_(e )n_(h)` `therefore n_(h)=(n_(i)^(2))/(n_(e ))=((1.5xx10^(16))^(2))/(4.95xx10^(22))` `thereforen_(h)=0.4545xx10^(10)` `~~0.45xx10^(10)` `~~4.5xx10^(9)m^(-3)` Here `n_(e ) GT gt n_(h)` so semiconductor is n-type. |
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