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The number of silicon atoms per m^(3) is5 xx 10^(28). This is doped simultaneously with 5 xx 10^(22) atoms per m^(3) of Arsenic and 5 xx 10^(20) per m^(3) atoms of Indium. Calculate the number of electrons and holes given that n_(i) = 1.5 xx 10^(16) m^(-3). Is the material n-type or p-type? |
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Answer» SOLUTION :Arsenic is PENTAVALENT and Indium is trivalent. `n_(e) = 5 xx 10^(22) - 0.05 xx 10^(22) = 4.95 xx 10^(22)` but `""n_(i)^(2) = n_(e)n_(h)` `THEREFORE ""n_(h) = (2.25 xx 10^(22))/(4.95 xx 10^(22)) = 0.454 xx 10^(10)` `n_(h) = 4.54 xx 10^(9) `PER `m^(3)` since `n_(e) gt n_(h)`, the material is n type. |
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