InterviewSolution
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InterviewSolution
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The number of solutions of equation `sin.(5x)/(2)-sin.(x)/(2)=2` in `[0,2pi]` is |
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Answer» Correct Answer - A Given equation can hold only if `sin.(5x)/(2)-1` and `sin.(x)/(2)=-1` i.e. `(5x)/(2)=2n pi +(pi)/(2)` and `(x)/(2)=2p pi -(pi)/(2)` (n `p in I`) For some possible p and n if there exists a solution, we must have `10 p pi-(5pi)/(2)=2n pi + (pi)/(2)` oe `10 p - 2n = 3` L.H.S. is even, R.H.S. is odd Hence, not possible for any p and n. |
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