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The number of solutions of `x+2+tanx=pi/2` in `[0, 2pi]` is |
Answer» `x+2+tanx = pi/2` `=> tanx = pi/2-x-2` Now, if we draw graphs of `tanx` and `pi/2-x-2`, we find that these two graphs intersects at two points from `[0,pi]`. Please refer to video to see the graphs. Thus, there are two solutions for the given equation. |
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