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InterviewSolution
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The number of telephone calls received at an exchange per interval for 250 successive one-minute intervals are given in the following frequency table.No. of calls (x):0123456No. of intervals (f):15242946544339Compute the mean number of calls per interval. |
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Answer» Let the assumed mean (A) = 3
Mean number of calls = A + \(\frac{\sum f_iu_i}{N}\) = 3 + \(\frac{135}{250}=\frac{885}{250}\) = 3.54 |
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