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InterviewSolution
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The number of telephone calls received at an exchange per interval for 250 successive one- minute intervals are given in the following frequency table:No. of calls(x)0123456No. of intervals (f)15242946544339Compute the mean number of calls per interval. |
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Answer» Let the assumed mean(A) = 3
Mean number of calls = \(A + \frac{Σ f_ix_i }{N }\) = 3 + \(\frac{135}{250 }\) = \(\frac{(750 + 135)}{250}\) = \(\frac{885}{250}\) = 3.54 |
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