1.

The number of telephone calls received at an exchange in 245 successive on 2-minute intervals is shown in the following frequency distribution :Number of calls01234567Frequency1421254551403912Compute the mean deviation about the median.

Answer»

Given, Numbers of observations are given. 

To Find: Calculate the Mean Deviation

Formula Used: Mean Deviation = \(\frac{\Sigma f|d_i|}{n}\) 

Explanation. Here we have to calculate the mean deviation from the median. 

So, We know, Median in the even terms \(\frac{3+5}{2}\)   , 

Therefore, Median = 4 

Let xi =Number of calls 

And, fi = Frequency

xifiCumulative Frequency|di|=|xi-4|Fi|di|
01414456
12135363
22560250
343103143
45115400
540194140
639233278
712245336
Total = 245Total = 366

N = 245 

Mean Deviation = \(\frac{\Sigma f|d_i|}{N}\) 

Mean deviation for given data = \(\frac{336}{245}\) = 1.49

Hence, The mean deviation is 1.49



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