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The number of turns in primary and secondary coils of a transformer is 50 and 200, respectively. If the current in the primary coil is 4 A, then current in the secondary coil isA. `1 A `B. 2AC. 4AD. 5A |
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Answer» (a) In a transformer, `therefore (N_(P))/(N_(s))=(I_(s))/(I_(p))=(50)/(200)=(I_(s))/(4) implies I_(s) =1A` |
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