1.

The number of turns in the coil of an A.C. generator are 100 and its cross-sectional area is 2.5 m^2. The coil is revolving in a uniform magnetic field of strength 0.3 T with the uniform angular velocity of 60 rad s^(-1). The value of maximum value produced is ...... kV.

Answer»

4.5
2.25
6.75
1.25

Solution :MAXIMUM INDUCED ENERGY ,
`V_m=NABW`
`=100xx2.5xx0.3 xx60`
=4500 V=4.5 KV


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