The numbers 1 to 12 inclusive areplaced in a hat. John takes anumber o

1.	The numbers 1 to 12 inclusive areplaced in a hat. John takes anumber out of the bag at random.What is the probability it is an oddnumber?
Answer» $\pink { Number \:of \: total \: possible \: outcomes}$ $= Numbers \: placed \: in \:a \:hat$ $= 12 \: --(1)$ $Favourable\:outcomes$ $= \{ 1,3,5,7,9,11\}$ $\blue { Number \:of \: favourable \: outcomes} = 6\:--(2)$ $\orange { Probability ( an \:odd \: number )}$ $= \frac{(2)}{(1)}$ $= \frac{6}{12}$ $= \frac{1}{2}$ THEREFORE., $\red{ Probability ( an \:odd \: number )}\green { =\frac{1}{2}}$ •••♪