The numerical aperture of a coaxial cable with core and cladding indices given by 2.33 and 1.4 respectively is(a) 3.73(b) 0.83(c) 3.46(d) 1.86I have been asked this question during an interview.Asked question is from Refractive Index and Numerical Aperture in section EM Wave Propagation of Electromagnetic Theory

The numerical aperture of a coaxial cable with core and cladding indic

1.	The numerical aperture of a coaxial cable with core and cladding indices given by 2.33 and 1.4 respectively is(a) 3.73(b) 0.83(c) 3.46(d) 1.86I have been asked this question during an interview.Asked question is from Refractive Index and Numerical Aperture in section EM Wave Propagation of Electromagnetic Theory
Answer» Correct option is (d) 1.86 For explanation: The NUMERICAL aperture is given by NA = √(N1^2 – n2^2), where n1 and n2 are the refractive indices of CORE and cladding RESPECTIVELY. On substituting for n1 = 2.33 and n2 = 1.4, we get NA = √(2.33^2-1.4^2) = 1.86.

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