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1. |
The numerical value of the length of Galilean telescope for normal vision is (assuming `f_0` and `f_e` as positive length)A. `f_(0)xxf_(e)`B. `(f_(0))/(f_(e))`C. `f_(0)+f_(e)`D. `f_(0)-f_(e)` |
Answer» Correct Answer - D `f_(0)-f_(theta)` |
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