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The objective of a microscope has a focal length of 1cm and diameter 0.5 cm. Using light of 600 dotA, is it possible to resolve the two point objects it they are separated by a distance of 10^(-6)m? |
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Answer» SOLUTION :Suppose the TWO objects are a distance `triangle x` apart. Since these objects are almost at the focal length of the objective, the ANGLE subtended by `triangle x`, `i.e., triangle phi approx (triangle x)/(f_0)` For the two objects to be CLEARLY resolved, `triangle phi gt triangle theta` (or) `(triangle x)/(f_0) gt (1.22 lambda)/(a) (triangle theta= (1.22 lambda)/(a))" (or) "triangle x gt (1.22 f_(0) lambda)/(a)` (or) `triangle x gt ((1.22)(1xx 10^(-2)m)(6000xx 10^(-10)m))/((0.5xx 10^(-2)))= 1.46xx 10^(-6)m` Because `10^(-6)m` is smaller than `1.46xx 10^(-6)m`, the two objects will not be resolved. |
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