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The odds against a certain event are 5 to 2, and the odds in favor of another event independent of the former are 6 to 5. Find the chance that one at least of the events will happen. |
Answer» P {First event does not happen} `=(5)/(5+2)=5/7` P{Second event does not happen} `=(5)/(5+6)=5/11` `therefore` {Both th events fail to happen} `5/7xx5/11=25/77` Therefore, the probability that at least one of the events will happen is 1- P(none of two happens) `=1-(25)/(77)=(52)/(77)` |
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