Saved Bookmarks
| 1. |
the ones digit of a two digit number is twice the tenth digit when the number is formed by receiving the digit is added to the original number the sum is 99 find the original number |
|
Answer» Let the tens DIGIT be y and the ones digit be x.The original number = 10Y + xThe reverse number = 10x + yIt is given that ones digit is twice the tens digit :]➳ x = 2y ............[Equation (i)]ACCORDING to question now,➳ 10x + y + 10y + x = 99➳ 11x + 11y = 99➳ 11 (x + y) = 99➳ x + y = 99/11➳ x + y = 9➳ y = 9 - x.........[Equation (ii)]Now, Substituting equation (ii) in equation (i) we get :➳ x = 2 (9 - x)➳ x = 18 - 2x ➳ 3x = 18➳ x = 18/3➳ x = 6Putting x = 6 in equation (ii) we get :➳ y = 9 - x➳ y = 9 - 6➳ y = 3Therefore, The original number = 10y + x = 10(3) + 6 = 30 + 6 = 36 |
|