1.

The only cations present in a slightly acidic solution are Fe^(3+),Zn^(2+) and Cu^(2+). The reagent that when added in excess to this solution would identify the separate Fe^(3+) in one step is

Answer»

2M HCl
6M `NH_(3)`
6 NAOH
`H_(2)S` gas

Solution :`Fe^(3+)` is a THIRD group radical, whose reagent is `NH_(4)OH` in presence of `NH_(4)CL`. So if 6M `NH_(3)` is added in the slightly ACIDIC (HCl) solution of IONS it will lead to the
`Fe^(3+)+Zn^(2+)+Cu^(2+) overset("6 M"NH_(3))to underset("Brown ppt.")(Fe(OH)_(3))+underset("Soluble")([Zn(NH_(3))_(4)]^(2+))+underset("Soluble")([Cu(NH_(3))_(4)]^(2+))`


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