Saved Bookmarks
| 1. |
The only correct combination is : |
|
Answer» (I)(ii)(P) `n_1=2 " " n_2=3` `DeltaP.E=27.2xx(Z)^2[1/n_1^2-1/n_2^2]` =`27.2xx(1)^2[1/4-1/9]=27.2xx5/36=3.78 ev` `DeltaE=13.6xx(1)^2[1/4-1/9]=1.88 ev` `barv=Rxx(1)^2[1/4-1/9]=(5R)/(36)` `lambda=36/(5R)` Angular momentum=`(3h)/(2pi)-(2h)/(2pi)=(h)/(2pi)` (II)Third line of paschen series of `He^+` ion `n_1=3 " " n_2=6` `DeltaP.E=27.2xx(2)^2[1/9-1/36]=9.06 ev` `DeltaE=13.6xx(2)^2[1/9-1/36]=4.54 ev` `barv=Rxx(2)^2[1/9-1/36]=R/3` `lambda=3/(R)` Angular momentum=`(6H)/(2pi)-(3h)/(2pi)=(3h)/(2pi)` (III)Lyman series limit for`Li^(+2)` ion `n_1=1 " " n_2=oo` `DeltaP.E=27.2xx(3)^2[1/1^2-1/oo^2]=27.2xx9=244.8 ev` `DeltaE=13.6xx(9)[1/1^2-1/oo^2]=122.4 ev` `barv=Rxx(3)[1/1^2-1/oo^2]=9R` (IV)`2^(ND)` line of Lyman series for `He^+` ion `n_1=1 " " n_2=3` `DeltaP.E=27.2xx(2)^2[1/1-1/9]=96.71 ev` `DeltaE=13.6xx(2)^2[1/1-1/9]=48.4 ev` `barv=Rxx(2)^2[1/1-1/9]=(32R)/9,lambda=9/(32R)` Angular momentum=`(3h)/(2pi)-(h)/(2pi)=(2h)/(2pi)=h/pi` |
|