1.

The orbital velocity of a satellite in a circular orbit just above the earth's surface is v_(0). The orbital velocity for a satellite orbiting in a circular orbit at an altitude of half of earth's radius is:

Answer»

`sqrt((3)/(2))v_(0)`
`sqrt((2)/(3)) v_(0)`
`(3)/(2)v_(0)`
`((2)/(3))v_(0)`

SOLUTION :`v_(0)=sqrt(gR)`
and orbital speed at a height h above the surfaceof earth is
`v=sqrt((GM)/(R+h))=sqrt((gR^(2))/(R+(R )/(2)))=sqrt((2)/(3)gR)`
`v= sqrt((2)/(3))*v_(0)`
So CORRECT choice is (b).


Discussion

No Comment Found

Related InterviewSolutions