The orbiting `v_(n) of e^(bar)` in the nth orbit in the case of positronium is x-field compared to that in the nth orbit in a hydrogen atom , where `x` has the valueA. 1B. `sqrt2`C. `1// sqrt2`D. 2

The orbiting `v_(n) of e^(bar)` in the nth orbit in the case of positr

1.	The orbiting `v_(n) of e^(bar)` in the nth orbit in the case of positronium is x-field compared to that in the nth orbit in a hydrogen atom , where `x` has the valueA. 1B. `sqrt2`C. `1// sqrt2`D. 2
Answer» Correct Answer - A `m v_(0)^(2) = K//r_(n)`. Since modified `m` is half and modified `r_(n)` is double, `v_(n)` remain the same as in `H`- atom.

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The orbiting `v_(n) of e^(bar)` in the nth orbit in the case of positronium is x-field compared to that in the nth orbit in a hydrogen atom , where `x` has the valueA. 1B. `sqrt2`C. `1// sqrt2`D. 2

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