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The order and degree of differential equation of all tangent lines to parabola `x^2=4y` isA. 1,2B. 2,2C. 3,1D. 4,1

Answer» Correct Answer - A
The equaiton of any tangent to `x^(2)=4y` is
`x=my+(1)/(m)`, where m is an arbitrary constant.
Differentiating this w.r.t. to x, we get
`1=m(dy)/(dx)rArr m=(1)/((dy)/(dx))`
Putting the value of m in x = `my+(1)/(m)`, we get
`x=(y)/((dy)/(dx))+(dy)/(dx)rArr((dy)/(dx))^(2)-x(dy)/(Dx)+y=0`,
Which is differential equation of order 1 and degree 2.


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