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The order and degree of differential equation of all tangent lines to parabola `x^2=4y` isA. 1,2B. 2,2C. 3,1D. 4,1 |
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Answer» Correct Answer - A The equaiton of any tangent to `x^(2)=4y` is `x=my+(1)/(m)`, where m is an arbitrary constant. Differentiating this w.r.t. to x, we get `1=m(dy)/(dx)rArr m=(1)/((dy)/(dx))` Putting the value of m in x = `my+(1)/(m)`, we get `x=(y)/((dy)/(dx))+(dy)/(dx)rArr((dy)/(dx))^(2)-x(dy)/(Dx)+y=0`, Which is differential equation of order 1 and degree 2. |
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