1.

The order in which the reagent must be used to separate the compound I-IV is:

Answer»

`NAOH,NaHCO_3,HCL`
`HCl, NaOH, NaHCO_3`
`NaHCO_3, NaOH, HCl`
`NaOH, HCl,NaHCO_3`

SOLUTION :It is SOLUBLE in `NaHCO_3` , I is soluble in NaOH and III is soluble in HCl.


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