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The order of differential equation of family of circles passing through intersection of `3x+4y-7=0` and `S=-x^(2)+y^(2)-2x+1=0` isA. 1B. 2C. 3D. 4 |
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Answer» Correct Answer - A Equation of family of circles is `(x^(2)+y^(2)-2x-2y+1)+lambda(3x+4y-7)=0` Arbitrary constants is 1 So, order is 1. |
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