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The oscillating magnetic field in a plane electromagnetic wave is given by B_(y)=(8xx10^(-6))sin[2xx10^(11)t+300pix]T (i) Calculate the wavelength of the electromagnetic wave. (ii) Write down the expression for the oscillating electric field. |
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Answer» SOLUTION :(i) Comparing the EQUATION of oscillating electric field with the STANDARD wave equation, we `therefore ` Wavelength of the electromagnetic wave `lambda=(2pi)/(k)=(2pi)/(300pi)=(1)/(150)m` (ii) The electromagnetic wave is propagating long `-ve`direction of x - axis and magnetic field is oscillating along x - axis, hence electric field must be oscillating along z- axis with an amplitude. `E_(0)=c.B_(0)=3xx10^(8)xx8xx10^(-6)=2.4xx10^(3)Vm^(-1)` Hence, expression for oscillating electric field is `E_(z)=2.4xx10^(3)SIN[2XX10^(11)t+300pix]Vm^(-1)`. |
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