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The other two 546 Tind the numbers013 Three consecutive natural numbers are such that the sum of the square of middle term exceeds thedifference of the squares of the other two by 69 find the number |
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Answer» Answer: Given x2−[(x+1)2−(x−1)2]=60 x2−[(x+1)2−(x−1)2]+60 x2=4x+60 ⇒ x2−4x−60=0 ⇒ x2−10x+6x−60=0 x(x−10)+6(x−10)=0 (x+6)(x−10)=0 ⇒ x=6,10 ∴ The numbers are 9,10,11 |
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