1.

The output current versus time curve of a rectifire is shown in the figure. The voltage value of output current in this case is

Answer» Correct Answer - C
c) Average value of output current is given by
`I_(av)` = `I_(av) = (int_(0)^(T//2)Idt)/(int_(0)^(T//2)dt)= (int_(0)^(T//2)I_(0)sinomegatdt)/(T//2)`
`=(2I_(0))/T[-(cosomegat)/(omega)]_(0)^(T//2)`
`=(2I_(0))/T[-(cos(omegaT//2)/(omega)+(cos0^(@))/(omega))]`
`=(2I_(0))/(omegaT)[(-cospi+cos0^(@))]=(2I_(0))/(2pi)[1+1]=(2I_(0))/(pi)`


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