InterviewSolution
Saved Bookmarks
| 1. |
The output of a step down transfomer is measured to be 24V when connected to a 12W light bulb. The value of the peak current is……..A |
|
Answer» `1/SQRT2` `therefore I_2=12/V_2=12/24=1/2A` Now according to formula, `I_(RMS)=I_m/sqrt2` `therefore I_m=sqrt2 I_(rms)=sqrt2 times 1/2=1/sqrt2 A` |
|