1.

The output of a step down transformer is measured to be 24 V when connected to a 12 watt light bulb. The value of the peak current is

Answer»

<P>`1/sqrt(2)` A
`sqrt(2)` A
0.083333333333333
`2sqrt(2)` A

Solution :Here P = 12 W and V = 24 V. Hence, `I = P/V = 12/24 = 0.5 A`
`therefore` Value of PEAK current `I_(m) = sqrt(2) I = sqrt(2) xx 0.5 = 1/sqrt(2)` A.


Discussion

No Comment Found

Related InterviewSolutions