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The output of the given circuit in figure. |
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Answer» would be zero at all times.  In above circuit, when a is positive with respect to b, diode is in forward bias condition and so taking its RESISTANCE zero, output voltage `V_(0)=V_(d )-V_(c )=0` In above circuit, when a is negative with respect to b, diode is reverse biased and so taking its resistance infinite, current becomes zero and so, `V_(a)=V_(d )` `therefore V_(a)-V_(b)=V_(d)-V_(b)` `therefore V_(a)-V_(b)=V_(d)-V_(c )""(because V_(b)=V_(c ))` `therefore V_(a)-V_(b)=V_(0)` `therefore V_(0) lt 0 "" (because V_(a) lt V_(b))` Thus, for each positive half cycle of A.C. supply, `V_(0)=0` and for each negative half cycle of A.C. supply `V_(0)` remains negative. HENCE, output voltage will be like output voltage of half wave rectifier with alternative negative half cycles. |
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