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The oxidation number of Fe in `K_(4)[Fe(CN))(6)]` isA. `+2`B. `-2`C. `+3`D. `+4` |
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Answer» Correct Answer - A `4 xx (+1) +x+6xx-1=0` or `x= +6-4= +2` Oxidation state of `F e= +2`. |
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