1.

The oxidation number of Fe in `K_(4)[Fe(CN))(6)]` isA. `+2`B. `-2`C. `+3`D. `+4`

Answer» Correct Answer - A
`4 xx (+1) +x+6xx-1=0` or `x= +6-4= +2`
Oxidation state of `F e= +2`.


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