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The oxidation number of `Ga` in `GaCl_(2)` isA. `+2`B. `+3`C. `+1`D. both `(2)` and `(3)` |
Answer» Correct Answer - D The compound `GaCl_(2)` actually exists as `Ga^(+)[GaCl_(4)]^(-)` which contains `Ga(+1)` as well as `Ga(+3)`. |
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