1.

The oxidation number of N in NH_(4)Cl is

Answer»

`+5`
`+3`
`-5`
`-3`

Solution :`NH_(4)CL""NH_(4)^(+)+Cl^(-)`
`overset(**)(N)H_(4)^(+)`
`x+4=+1, x=1-=-3`.


Discussion

No Comment Found