1.

The oxidation number of nickel in K_(4)[Ni(CN)_(4)] is

Answer»

`-2`
`-1`
`+2`
`0`

Solution :`K_(4)[Ni(CN)_(4)]`
`4XX(+1)+x+4xx(-1)=0`
`+4+x-4=0 IMPLIES x=0`.


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